4.9x^2+7x=750

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Solution for 4.9x^2+7x=750 equation:



4.9x^2+7x=750
We move all terms to the left:
4.9x^2+7x-(750)=0
a = 4.9; b = 7; c = -750;
Δ = b2-4ac
Δ = 72-4·4.9·(-750)
Δ = 14749
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{14749}=\sqrt{1*14749}=\sqrt{1}*\sqrt{14749}=1\sqrt{14749}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1\sqrt{14749}}{2*4.9}=\frac{-7-1\sqrt{14749}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1\sqrt{14749}}{2*4.9}=\frac{-7+1\sqrt{14749}}{9.8} $

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